Trivia Game

[jamesglewisf]

I posted this in another forum, so if you saw the answer there, you don't get to answer.

What famous Texas Rock 'n Roller did Kenny Rogers help make famous?

[blinc]

I was thinking Garth Brooks for some reason... but he's not a rock 'n roller. :D

[jamesglewisf]

For some reason, I think Garth is from Oklahoma. Good guess though!

[TWTCommish]

Aw heck, I dunno. Travis whats-his-name? :)

[jamesglewisf]

Keep guessing.

[jamesglewisf]

OK, it's been five days. Kenny Rogers took Don Henley to California, where he helped found the Eagles.

Somebody give another trivia question.

[TWTCommish]

Alright, I'll give it a go:

Most people know that Hank Aaron is the all time baseball Home Run King, and that Babe Ruth is second. This is easy for most baseball fans: who is third?

Bonus: how many did he have? :D

[jamesglewisf]

The same night he also broke the NL record for runs scored. The answer to your question is the player whose NL runs-scored record he broke.

[TWTCommish]

Wha? I didn't follow a word of that. :)

[jamesglewisf]

Sorry, the same night that Aaron broke Babe Ruth's home run record, he also broke the NL runs-scored record. The person who is in third place for home runs is the person whose NL runs-scored record was broken.

[TWTCommish]

That's interesting - I didn't know that. Anyone have an idea on the answer, though?

[blinc]

Wild guess here.. was it Joe Dimaggio (Spelling)?

[TWTCommish]

Nope, he's not #3 on the all time HR list. :)

C'mon, people! Am I the only baseball dude here?

[TTP]

I'm not real big on baseball, but if I had to guess I'ld say it was Mayes? Willie Mays?

[TWTCommish]

DING-DING-DING! At long last. :)

He had 660 total (yes, that's off the top of my head)

Your turn for a question, TTP :)

[TTP]

Woohoo! It's a miracle!

Ok, my trivia for all you would be sports related as well:

Three times the NBA has had Co-Rookies of the year, name the years and players involved.

[TWTCommish]

I can only name one (not a Basketball fan): Grant Hill and Jason Kidd, in 94 I believe.

[TTP]

Ok we have one so far: Grant Hill who was then playing for Detroit and Jason Kidd who started with Dallas shared the Rookie of the Year honor in the 1994-95 season.

Two left, for one think Chicago/Houston and even more recent than 94. For the other think Boston/Portland and the year a musician by the name of Jimi Hendrix past-away.

[theyeti]

Of course! Elton Brand and Steve Francis. As for the other one... i'm thinking Kareem Abdul-Jabbar? Oh wait, Boston or Portland.. hmmmm... no clue. :(

[TTP]

Yep that makes two:
Grant Hill/Jason Kidd 94-95
Elton Brand/Steve Francis 99-00
The last pair was in the 70-71 year...see if that helps any. :)

[TTP]

Ok, the last 'pair' was in 70.

Dave Cowens of Boston and Geoff Petrie of Portland.

[TTP]

New one!

How many letters does the Hawaiian alphabet have?

[Debby]

Oh my gosh thats hard!! I have no clue!!!!

[TWTCommish]

Is it 13?

[jamesglewisf]

I'm guessing 26.

[TTP]

13 wins it!

Your go!

[TWTCommish]

Hehe - I remember hearing that it was either 12 or 13. So it wasn't really a total guess or anything. :)

Alright, here's mine:

If 5x + 4 * yx = 10x - y, what does x equal? :D

Just kidding...how about this: List the pieces in chess from most valuable to least valuable - sounds easy, but it's tricky. There is a "tie" in there somewhere, and they do have factual values. :)

[TTP]

X=1 ;)

For your other question it goes:

King
Queen
Rook
Bishop
Knight
Pawn

If I remember correctly.
9, 5, 3, 3, 1 with the King being invaluable since if he is captured the game is over...

[TWTCommish]

Obviously it starts King, Queen, and ends in Pawn, but I'm virtually sure that one of the three "middle" pieces is more valuable than the other two. If I'm wrong, I apologize!

x = 1? I didn't bother to do the problem, that the real answer? :)

[TTP]

Hehe, yeah I'm pretty sure x=1. :)

King: Invaluable
Queen: 9
Rook: 5
Bishop: 3
Knight: 3
Pawn: 1

I had that earlier, I just had it split up w/o the numbers actually by names.

[TWTCommish]

Nope, sorry! The rook is not the most valuable of the 3...like I said, I'm virtually sure of this, but would yield if sufficient evidence was presented. :)

[TTP]

I shall go look for some...this could take awhile.

[TTP]

I've been to two sites and they both offer the same information.
One was here: http://www.kasparovchess.com/serve/templates/folders/show.asp?p_docID=9725&p_docLang=EN
And the person here made a very good point:
Another thing to bear in mind is that chess is a dynamic game and these values are not fixed in granite. For example, there are positions where a knight can be more valuable than a queen.

All you really have here is a rough guide as to when and when not to exchange pieces...for example, in general, you will be doing quite well to exchange a rook and a knight for a queen, since 5 plus 3 is 8 and a queen is worth 9.
Even the approximations are not generally agreed...some people would say a rook is only worth 4.5...and maybe a bishop is worth 3.2. Whatever the case, you should not rely totally on these values, but should make your own judgments based on what you think is important in the position.

Material may be measured in terms of the sum total of the value of the pieces and pawns concerned.

And the other here: http://www.chesscorner.com
*Click learn, click setting up the board*

[theyeti]

i was always taught that the knight was slightly more valuable than the bishop, but i'm not sure that's correct...

and i got x=1 too. :)

[TTP]

Anybody have any trivia??

[DkTahg]

Star Trek II Wrath of Kahn. This is easy.
1)What ship was Kahn cyrogenically frozen on, and what year was it.
2)Why was the USS Relient in the Ceti Alpha sector?
3)Bonus question: What is the Relient's NCC number and prefix number?

[TTP]

I'm going to the cheap seats! I haven't a clue...not a fan to put it mildly. {toothy}

[blinc]

I'm a big Sci-Fi fan, but I haven't seen this movie in so long, I don't remember 1 and 2 at all. Number three... if I saw the movie last night, I probably still couldn't have remembered it. Aargh! These are hard ones DkTahg! :)

[DkTahg]

Heres a hint for the first two.
The name of the ship that khan was frozen on has somthing to do with the study of plants. The year he was frozen would be 3 years ago.
The second part of the problem is actully the main plot point for the this movie, the next movie "The Search for Spock" and a little bit of the fourth movie "The Voyage Home." It has somthing to do with a secret project that superficially resembled somthing that was explained in the Bible.

[blinc]

*jumps up and down* {grblob}
The Genesis Project! {grblob} The Genesis Project!! Woo Hoo!! {grblob}

Still working on the others!!

[DkTahg]

Right you are! The Reliant went to Ceti Alpha system to look for a sutable "dead" planet to continue the "Gensis Project."

[blinc]

Uncle! Uncle! Uncle!
Aaagh! I hate giving up on riddles, but I just can't remember the names! This thread has driven me nuts DkTahg! Ok, so ya win one against us, I do believe you've stumped us all with this bit of trivia. {grblob}

[Alec]

SS Botany Bay

[DkTahg]

Yes, Kahn was cyrogenically frozen on the SS Botany Bay. Way to go! {grblob}.

[Zephyrus]

Aaaahh, just one question for everyone...

How do you solve an equation with two unknowns from just the one equation?? If you get x=1, then y=1 as well, but that's not the solution, just one of the range of possible ones...it's unsolvable unless you have a second equation to work from ;)

[DkTahg]

Yes you can. All you have to do is take the inverse of the function. example

y=2x+1
take the inverse of this and get
y=x/2-1/2
Set up your equation
0=2x+1-y
0=x/2-1/2
solve for x and get x=-1
plug back into first equation and solve for y and get y=-1
Plug both back into first equation to check
(-1)=2(-1)+1 and get
-1=-1
the statement is true so you solution is x=-1 y=-1

you can check this way too. graph both function on the same graph and then graph y=x over them. Where all three graphs intercept, is the solution set. This set should be
(-1,-1). But after all, this is setting the equation to its inverse, so domain and range switch. However, you do get a second equation but you are right, you cant solve a 2 variable equation with one equation. :)

[Zephyrus]

I really don't unerstand how you can turn y=2x+1 into y=x/2-1/2...it's a bit confusing!

[Karenluvs6]

Originally posted by DkTahg
Yes you can. All you have to do is take the inverse of the function. example

y=2x+1
take the inverse of this and get
y=x/2-1/2
Set up your equation
0=2x+1-y
0=x/2-1/2
solve for x and get x=-1
plug back into first equation and solve for y and get y=-1
Plug both back into first equation to check
(-1)=2(-1)+1 and get
-1=-1
the statement is true so you solution is x=-1 y=-1

you can check this way too. graph both function on the same graph and then graph y=x over them. Where all three graphs intercept, is the solution set. This set should be
(-1,-1). But after all, this is setting the equation to its inverse, so domain and range switch. However, you do get a second equation but you are right, you cant solve a 2 variable equation with one equation. :)


{eek2}

where did you say you're from again?????
j/k

[Alec]

I think the inverse of y = 2x + 1 is x = y/2 - 1/2.

[Zephyrus]

yep you're right, but it's not the other way round like he put it :)

[blinc]

Karen... they're from that planet the aliens on "3rd Rock from the Sun" are from. Only these guys are directly related to "The Big Giant Head"! {einstein}

Geesh, where's my aspirin at? {toothy}

[DkTahg]

I just put my equation into slope intercept form :)
y=mx+b

I think in terms of "undoing" and switching the Domain with the Range. like f(x)=e^x and the inverse is f^-1(x)=ln(x)
These functions undo each other.

Heres how I work an inverse problem.
1)f(x)=2x+3
2) Replace f(x) with y
3) y=2x+3
4) Now switch the domain with the range. Or replace x with y and y with x.
5)x=2y+3
6) Solve for y to get it into slope intercept form
7) y=(x/2)+(3/2)
8) now replace y with f^-1(x)
9) f^-1(x)=(x/2)+(3/2)

Plug in any number for x in f(x) and then plug the answer back into x for f^-1(x) and you will find that you end up with the original number.

If you graph both functions, you'll notice that they "reflect" each other about the y=x function.

This is how I was taught to solve these problems.
Like in almost eveything in algebra, there is always two ways to skin a cat! =^.^=

[Zephyrus]

Thanks Dk, I got it :)

The Big Giant Head *gives the salute* ?? I think they're too close for Dk :) :) :)